24 = 4*3*2*1
The first digit has 4 choices for its digit. The second digit has 6 choices and the third has 3. The solution would simply be 4*6*3=72 three digit numbers.
24
-1230
Twelve of them.
1234
The first digit has 4 choices for its digit. The second digit has 6 choices and the third has 3. The solution would simply be 4*6*3=72 three digit numbers.
24
1234
4 x 3 x 2 ie 24
-1230
Twelve of them.
what is the greatest 4-digit number you can make with the digit 0,1,2,3, and 4
1234, if you don't repeat any.
1234
There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125
It is a number with two digits in it. So it goes into the "tens" place of the numbers. Basically any whole number from 10 to 99. See how any number between those numbers only has 2 numbers, or digits that make up the number? 9 would only be a single-digit number, and 100 would be a triple-digit number.
The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).