(13 x 12 x 11 x 10)/(4 x 3 x 2 x 1) = 715 of them
Number of Prime Numbers from 1 to 100 is 25. From 1 to 50 it was 15 From 50 to 100 it was 10
apart from1, 3x3x3x3, so four I suppose
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47.
It appears 20 times.
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97
Number of Prime Numbers from 1 to 100 is 25. From 1 to 50 it was 15 From 50 to 100 it was 10
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25 of them.
There are no 5 odd numbers whose sum is 50. (The sum of 5 odd numbers is an odd number whereas 50 is an even number.)
apart from1, 3x3x3x3, so four I suppose
There are more in 1 to 25.
There are many answers: if numbers can be repeated-1)all '1s' and all '3s' 2)4'1s' and so on....
Well, it will be slow and inefficient: rec_strcpy (char *to, char *from1, char *from2) { . if (*from1) { . . *to = *from1; . . rec_strcpy (to+1, from1+1, from2); . } else if (*from2) { . . *to = *from2; . . rec_strcpy (to+1, from1, from2+1); . } else { . . *to = '\0'; . } }
Example1:sprintf (to, "%s%", from1, from2);Example2:size_t len1= strlen (from1);memcpy (to, from1, len1);strcpy (to+len1, from2);
2, 3, 5, 7, 11, 13, 17, 19, 23.
2 3 5 7 11 13 17 19 23 29 31 37 41.
from1 to 5