There are 15 of them.
The product of the GCF and LCM of a pair of numbers is equal to the product of the numbers.
If you are not allowed to repeat the digits then the answer is clearly 0.If you are allowed to repeat digits then the only way you can possibly reach a product of 4 is by using a combination of 3 "1's" and 2 "2's". The possible combinations are therefore:22111212112112121112122111212112112112211121211122Thus there are 10 numbers which meet the criteria.
121
Yes.
When the two numbers are relatively prime.
The product of the GCF and LCM of a pair of numbers is equal to the product of the numbers.
If you are not allowed to repeat the digits then the answer is clearly 0.If you are allowed to repeat digits then the only way you can possibly reach a product of 4 is by using a combination of 3 "1's" and 2 "2's". The possible combinations are therefore:22111212112112121112122111212112112112211121211122Thus there are 10 numbers which meet the criteria.
The product of the GCF and LCM is equal to the product of the original two numbers.
I believe here are 51 such numbers.
No, the product of two prime numbers is unique.
Expressed in digits, this is equal to 14,500,000.
Two (or four) digits added together cannot equal 42. Two-digit numbers multiplied together cannot equal 82.
17 multiplied by 13 is equal to 221. This can be calculated by multiplying the units digits of the numbers (7 and 3) to get 21, and then adding the product of the tens digits (1 and 1) to get 22. Therefore, the result is 221.
none.
3721
21.
factors