it's 36. Only use 50c or $1 or $2, 3 ways only use 50c and $1, 9 ways, only use 50c and $2, 4 ways, only use $1 and $2, 4 ways. use 50c, $1 and $2, 16 ways. total is $36
3 dimes 13 nickles 5 pennies
$10 50c
More information is needed. Please post a new and separate question with the coin's country of origin. Many countries have 50¢ coins.
$490 20*.50=$10 500-10=$490
One combination anyway: American: 3.5 dollars in 50c is 7 coins 2 dollars in quarters = 8 coins 5 dimes = 5 coins Euro: 3.5 euro in 50c is 7 coins 2.40 euro in 20c is 12 coins and 1 10 cent coin
大变
16 $0.50 coins
it's 36. Only use 50c or $1 or $2, 3 ways only use 50c and $1, 9 ways, only use 50c and $2, 4 ways, only use $1 and $2, 4 ways. use 50c, $1 and $2, 16 ways. total is $36
Well, isn't that a happy little math problem we have here! If Ann has more 50c coins than 10c coins and the total value is $5, we can figure out that she must have 4 10c coins. Let's give Ann a little encouragement as she counts her coins and solves this puzzle.
3 dimes 13 nickles 5 pennies
$2, $1, 50c, 20c, 20c.
Three. 1x $10, 1x $1 and 1x 50c
If in america, 3 quarters make 75c. With the euro, a 50c, a 20c, and a 5c make 75c
umm so 1 euro+50c+20c+5c=1.75 euro:)
Indeed. 74 cents can be made with the following set of 7 coins: 50c 10c 10c 1c 1c 1c 1c
Tentatively I will say $4.35, with for instance: 19 x 20c 1 x 50c 1 x 5c It's possible that a rigorous method exists, but this is just a fudged guess. Any advances on it?