35
Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.
i think there are 18 digit 5s.
To win the jackpot there are 5,006,386 combinations for the five numbers x 35 powerball choices, so there are 175,223,510 combinations for picking the jackpot combination.
35 or 243
35
Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.
how mant 5-number combinations are there with tnumbers 1 thru 35, please list them all?
There are: 35C3 = 6545 combinations
There are 35C4 = 35*34*33*32/(4*3*2*1) = 52,360 combinations.
35
7C3 = 7*6*5/(3*2*1) = 35 combinations.7C3 = 7*6*5/(3*2*1) = 35 combinations.7C3 = 7*6*5/(3*2*1) = 35 combinations.7C3 = 7*6*5/(3*2*1) = 35 combinations.
i think there are 18 digit 5s.
To win the jackpot there are 5,006,386 combinations for the five numbers x 35 powerball choices, so there are 175,223,510 combinations for picking the jackpot combination.
You did not give us the set to work with...
35.
35 or 243