Since 5 is greater than 2, there are 0 complete groups of 5 that can fit into 2. In mathematical terms, 2 divided by 5 equals 0.4, which indicates that only a fraction of 5 fits into 2. Therefore, the answer is 0 complete 5s.
21 5s
103.4
20
3675 ÷ 5 = 735
3/5 or 0.6 of them.
37 ÷ 5 = 7 2/5 = 7.4 or it can also be considered as 37 ÷ 5 = 7 remainder 2.
175 x 5 = 875
5 x 30 = 150
27 x 5 = 135
In a neutral zinc atom, there are 2 electrons in the 4d orbital and 2 electrons in the 4s orbital. Therefore, there are no 5s electrons in a zinc atom.
5s - 6 = 2s, ie 5s - 2s = 6, ie 3s = 6, ie s = 2
In the Rb atom, the electron configuration is [Kr]5s^1. This means there is 1 electron in the 5s sublevel of the Rb atom.