It depends on the dimensions of the room. As an extreme example, if the room is 1 ft * 1500 ft , not a single table will fit.
The fact that the tables are round is a distraction as (since most rooms are rectangular) each table would have to fit in a square 48 inches by 48 inches (or 4 foot by 4 foot). This means that each table will take up 4*4 = 16 square feet. If you divide 16 into 600 you come up with 37.5 tables so in theory you could fit 37 tables into it. However, if the room was 1 foot wide and 600 feet long you would not be able to fit any tables into it. Only if the room was irregularly shaped could you fit the maximum number of 4 ft round tables, each of which has the area (pi)(22) or about 12.57 square feet. A total area of 600 square feet would fit the "area" of 47.75 of the tables. By arranging the tables in staggered rows, a rectangular room could fit between 37 and 42 tables, depending on the room width.
To determine how many 60-inch round tables can fit in a 4000 square foot room, first calculate the area of one table. A 60-inch round table has a diameter of 5 feet, giving it a radius of 2.5 feet. The area of one table is roughly 19.63 square feet (using the formula πr²). Dividing the total room area (4000 square feet) by the area of one table gives approximately 203 tables, but this doesn't account for space needed for movement and accessibility, so the practical number would be lower.
meow?
1500 sq. ft = 1,393,546 sq. cm.
The area of each table is (pi)(302) square inches or about 2827.4 square inches.You would divide that into 200 square feet, which is 28800 square inches, and find that you could fit the area of a 60-inch table 10.18 times in a 200 square foot area.But, since there is insufficient space to benefit from arranging the tables, each table is going to take up more or less a 5 foot square area (60 inches by 60 inches). For an area of 10 x 20 feet, you would fit 8 tables (2 rows of 4) and for an area 5 x 40 feet, again 8 tables (1 row of 8).Only if the area is irregularly shaped could you fit 9 tables, and only if it had curved boundaries could you fit 10 tables.
The fact that the tables are round is a distraction as (since most rooms are rectangular) each table would have to fit in a square 48 inches by 48 inches (or 4 foot by 4 foot). This means that each table will take up 4*4 = 16 square feet. If you divide 16 into 600 you come up with 37.5 tables so in theory you could fit 37 tables into it. However, if the room was 1 foot wide and 600 feet long you would not be able to fit any tables into it. Only if the room was irregularly shaped could you fit the maximum number of 4 ft round tables, each of which has the area (pi)(22) or about 12.57 square feet. A total area of 600 square feet would fit the "area" of 47.75 of the tables. By arranging the tables in staggered rows, a rectangular room could fit between 37 and 42 tables, depending on the room width.
If you want the price per square foot, divided 4000 by 1500. The price is 2.66 per square foot.
The 1500 square foot building would have a rental cost of $21,000. You don't specify the terms of any lease.
To determine how many 60-inch round tables can fit in a 4000 square foot room, first calculate the area of one table. A 60-inch round table has a diameter of 5 feet, giving it a radius of 2.5 feet. The area of one table is roughly 19.63 square feet (using the formula πr²). Dividing the total room area (4000 square feet) by the area of one table gives approximately 203 tables, but this doesn't account for space needed for movement and accessibility, so the practical number would be lower.
meow?
1500 sq. ft = 1,393,546 sq. cm.
$26,250.00. $17.50 x 1500.
25 tables. Since each table is 16 square feet each, divide the total space available (400sq ft) by 16.
If you describe a table as being 6 foot, that would normally mean that it is 6 feet long, and rectangular in shape rather than round. Only round tables have a diameter. The term doesn't apply to rectuangular tables.
The area of each table is (pi)(302) square inches or about 2827.4 square inches.You would divide that into 200 square feet, which is 28800 square inches, and find that you could fit the area of a 60-inch table 10.18 times in a 200 square foot area.But, since there is insufficient space to benefit from arranging the tables, each table is going to take up more or less a 5 foot square area (60 inches by 60 inches). For an area of 10 x 20 feet, you would fit 8 tables (2 rows of 4) and for an area 5 x 40 feet, again 8 tables (1 row of 8).Only if the area is irregularly shaped could you fit 9 tables, and only if it had curved boundaries could you fit 10 tables.
$21,000
it is 1.9999999999