Anything from 21 to 30 beads, depending on their orientation.
At the girdle, this stone would measure about 6.5 mm.
There are exactly 25.4 mm for each inch. Therefore, there are 16*25.4=406.4 mm in 16 inches. Assuming that 4 mm beads occupy exactly 4 mm along the length, this would allow 406.4/4=101.6 beads to occupy that length. In other words, you would have 101 beads but only 6/10=3/5 of a bead until you got to the 16 inch mark. Thus the answer is 101 whole beads with a little bit left over given the assumption about bead length.As a practical matter, the above calculation assumes that the beads are to occupy the entire "strand" and that the length given is not the entire length of the beading string itself, which would be longer in order to tie it. if the beads are actually a little shorter than 4mm or they don't have to be aligned along the length of the beading string exactly, you might be able to get 102 or more beads "along" the length.Read more: How_many_8mm_beads_in_16_inches
A round, brilliant cut diamond measuring 6.5 mm at the girdle weighs about one carat.
There are 10mm in one centimetre so 98 mm is 9.8 cm. 10 mm in one cm and 100cm in one meter. so mm goes into cm not the other way round.
Anything from 21 to 30 beads, depending on their orientation.
11
Depending on the depth of the round brilliant cut, the measurement can be estimated at about 8 mm at the girdle.
At the girdle, this stone would measure about 6.5 mm.
Assuming that "1 inch round circle" refers to a circle whose circumference is 1 inch, its area is 51.34 sq mm.
A four-carat round cut diamond measures about 10mm at the girdle. Different cuts would have various mm measurements for each weight.
depends on how big those beads are and how you want to put them together If you want to use just those beads to make up a necklace then maybe 2-3 but again its all depending on the size of the beads. If you put seedbeads in between then you can make them stretch and make 10 or so necklaces.. Can you give more info on the size in mm of the beads.
There are exactly 25.4 mm for each inch. Therefore, there are 16*25.4=406.4 mm in 16 inches. Assuming that 4 mm beads occupy exactly 4 mm along the length, this would allow 406.4/4=101.6 beads to occupy that length. In other words, you would have 101 beads but only 6/10=3/5 of a bead until you got to the 16 inch mark. Thus the answer is 101 whole beads with a little bit left over given the assumption about bead length.As a practical matter, the above calculation assumes that the beads are to occupy the entire "strand" and that the length given is not the entire length of the beading string itself, which would be longer in order to tie it. if the beads are actually a little shorter than 4mm or they don't have to be aligned along the length of the beading string exactly, you might be able to get 102 or more beads "along" the length.Read more: How_many_8mm_beads_in_16_inches
20.
There are exactly 25.4 mm for each inch. Therefore, there are 16*25.4=406.4 mm in 16 inches. Assuming that 8mm beads occupy exactly 8mm, this would allow 406.4/8=50.8 beads to occupy that length. In other words, you would have 50 beads but only 8/10=4/5 of a bead until you got to the 16 inch mark. Thus the answer is 50 whole beads with a little bit left over given the assumption about bead length. If the beads are actually a little shorter or they don't have to be aligned along the length exactly, you might be able to get 51 beads "along" the length.
A 9 mm round out of a Glock 17 is 1148 feet per second
No, 94 mm is equal to approximately 3.7 inches, which means it will not fit inside a 3-inch tube.