I am not stupid enough to try and list them since there are 55*54*53*52*51*50/(6*5*4*3*2*1) = 28,989,675 combinations. nPr=permutation while nCr=combination. The question is how many combination of 6 are there in 55 numbers. So the answer should be based on the formula: nPr = n!/(n-r)! where ! is factorial and nCr = nPr/r! = n!/{(n-r)*r!} ; So using the formula should look likr this 55C6 = 55!/{(55-6)!*6!} = 55!/(49!*6!) = 28,989,675
It is: 55C6 = 28,989,675
262
677
50. 51. 52. 53. 54. 55. That is 6 numbers.
I am not stupid enough to try and list them since there are 55*54*53*52*51*50/(6*5*4*3*2*1) = 28,989,675 combinations. nPr=permutation while nCr=combination. The question is how many combination of 6 are there in 55 numbers. So the answer should be based on the formula: nPr = n!/(n-r)! where ! is factorial and nCr = nPr/r! = n!/{(n-r)*r!} ; So using the formula should look likr this 55C6 = 55!/{(55-6)!*6!} = 55!/(49!*6!) = 28,989,675
It takes 28,989,675 to win the jackpot in this 6/55 lotto. . . (without repeated 6-number combination)
582,236,491
It is: 55C6 = 28,989,675
262
42C6 = 5245786
677
software with winning combination for the florida pick 6 game what are these numbers
50. 51. 52. 53. 54. 55. That is 6 numbers.
61
40 dhjfdsm dlgkDRFRt
7 of them. Remember, that in a combination the order of the numbers does not matter.