18/7
210 ÷ 7 = 30
7, remainder 2
8 / 7 in long division is however many 7s go into 8. so there's 1x 7 in 8 with 1 remainder. For this example, assume every number beyond is a 10, multiplied by the remainder. so, it'd be 7s into 10, which is 1 again. Then 7s into 30, which is 4. Then 7s into 20, which is 2. Then 7s into 60, which 8. Then 7s into 40, which is 5. Then 7s into 50, which is 7. And this is a reoccuring number, making it 1.142857142857 and so on.
999 ÷ 7 = 142 remainder 5
18/7
There are: 777/7 = 111
210 ÷ 7 = 30
7, remainder 2
As in, how many times does 7 go into 1400? 1400 / 7 = 200
8 / 7 in long division is however many 7s go into 8. so there's 1x 7 in 8 with 1 remainder. For this example, assume every number beyond is a 10, multiplied by the remainder. so, it'd be 7s into 10, which is 1 again. Then 7s into 30, which is 4. Then 7s into 20, which is 2. Then 7s into 60, which 8. Then 7s into 40, which is 5. Then 7s into 50, which is 7. And this is a reoccuring number, making it 1.142857142857 and so on.
999 ÷ 7 = 142 remainder 5
7.143, approximately. 50 ÷ 7 = 7 with remainder 1
630/7 = 90 so there are 90 7s in 630
124 ÷ 7 = 17 with remainder 5
492 ÷ 7 = 70 with remainder 2
there is one 7 for every 10 numbers. There are 20 sets of ten going up to 201, so 20 7s there. There is also the 70s, and 170s, which each have 10 7s, making 20 more 7s. In total, the number 7 appears 40 times from 7 to 201.