100
18/7
7, remainder 2
210 ÷ 7 = 30
Five 7s can go into 35. This is because when you divide 35 by 7, the result is 5 (35 ÷ 7 = 5). Therefore, you can fit five 7s into 35 without exceeding it.
8 / 7 in long division is however many 7s go into 8. so there's 1x 7 in 8 with 1 remainder. For this example, assume every number beyond is a 10, multiplied by the remainder. so, it'd be 7s into 10, which is 1 again. Then 7s into 30, which is 4. Then 7s into 20, which is 2. Then 7s into 60, which 8. Then 7s into 40, which is 5. Then 7s into 50, which is 7. And this is a reoccuring number, making it 1.142857142857 and so on.
18/7
There are: 777/7 = 111
7, remainder 2
210 ÷ 7 = 30
Five 7s can go into 35. This is because when you divide 35 by 7, the result is 5 (35 ÷ 7 = 5). Therefore, you can fit five 7s into 35 without exceeding it.
As in, how many times does 7 go into 1400? 1400 / 7 = 200
8 / 7 in long division is however many 7s go into 8. so there's 1x 7 in 8 with 1 remainder. For this example, assume every number beyond is a 10, multiplied by the remainder. so, it'd be 7s into 10, which is 1 again. Then 7s into 30, which is 4. Then 7s into 20, which is 2. Then 7s into 60, which 8. Then 7s into 40, which is 5. Then 7s into 50, which is 7. And this is a reoccuring number, making it 1.142857142857 and so on.
999 ÷ 7 = 142 remainder 5
630/7 = 90 so there are 90 7s in 630
7.143, approximately. 50 ÷ 7 = 7 with remainder 1
492 ÷ 7 = 70 with remainder 2
124 ÷ 7 = 17 with remainder 5