100
To find how many 7s are in 93, you can divide 93 by 7. When you do this calculation, 93 ÷ 7 equals approximately 13.29. This means there are 13 full 7s in 93, with a remainder.
18/7
7, remainder 2
210 ÷ 7 = 30
To find how many times 7 fits into 31, you can divide 31 by 7. Doing the calculation, 31 ÷ 7 equals approximately 4.43. This means there are 4 whole 7s in 31, with a remainder. Thus, 31 contains four 7s.
To find how many 7s are in 93, you can divide 93 by 7. When you do this calculation, 93 ÷ 7 equals approximately 13.29. This means there are 13 full 7s in 93, with a remainder.
18/7
There are: 777/7 = 111
210 ÷ 7 = 30
7, remainder 2
To find how many times 7 fits into 31, you can divide 31 by 7. Doing the calculation, 31 ÷ 7 equals approximately 4.43. This means there are 4 whole 7s in 31, with a remainder. Thus, 31 contains four 7s.
Five 7s can go into 35. This is because when you divide 35 by 7, the result is 5 (35 ÷ 7 = 5). Therefore, you can fit five 7s into 35 without exceeding it.
As in, how many times does 7 go into 1400? 1400 / 7 = 200
Four 7s go into 28, as 28 divided by 7 equals 4. This means that if you add 7 four times (7 + 7 + 7 + 7), you will reach 28.
8 / 7 in long division is however many 7s go into 8. so there's 1x 7 in 8 with 1 remainder. For this example, assume every number beyond is a 10, multiplied by the remainder. so, it'd be 7s into 10, which is 1 again. Then 7s into 30, which is 4. Then 7s into 20, which is 2. Then 7s into 60, which 8. Then 7s into 40, which is 5. Then 7s into 50, which is 7. And this is a reoccuring number, making it 1.142857142857 and so on.
999 ÷ 7 = 142 remainder 5
7.143, approximately. 50 ÷ 7 = 7 with remainder 1