First, calculate the volume of the hole in cubic inches: (18 \times 48 \times 12 = 10,368) cubic inches. Since there are 1,728 cubic inches in a cubic foot, convert the volume to cubic feet: (10,368 \div 1,728 \approx 6) cubic feet. An 80-pound bag of material typically covers about 0.6 cubic feet, so you would need approximately (6 \div 0.6 = 10) bags to fill the hole.
To determine how many ten-pound bags of ice will fill a 48-quart cooler, we first need to convert quarts to pounds. A quart of ice weighs approximately 2.2 pounds, so a 48-quart cooler can hold about 105.6 pounds of ice (48 quarts x 2.2 pounds/quart). Dividing this by the weight of a ten-pound bag of ice, you would need about 10.56 bags, which means you would need 11 bags to fill the cooler completely.
To calculate the number of 94-pound bags of Portland cement needed to fill a hole that is 8 inches in diameter and 10 feet deep, first determine the volume of the hole. The volume (V) of a cylinder is given by the formula V = πr²h. The radius (r) is 4 inches (0.33 feet) and the height (h) is 10 feet, resulting in a volume of approximately 10.99 cubic feet. Since one cubic foot of cement weighs about 94 pounds, you would need around 1,032 pounds of cement, equating to about 11 bags of 94-pound Portland cement (1,032 ÷ 94 ≈ 11).
120 50-pound bags.
One cubic yard is equivalent to 27 cubic feet. A 60-pound bag of Quikrete typically yields about 0.45 cubic feet of concrete. Therefore, to fill one cubic yard, you would need approximately 60 bags of 60-pound Quikrete bags (27 cubic feet ÷ 0.45 cubic feet per bag = 60 bags).
To find out how many 0.25 kg bags you can fill with 5.25 kg of jellybeans, divide 5.25 by 0.25. This calculation gives you 5.25 ÷ 0.25 = 21. Therefore, you can fill 21 bags of 0.25 kg each.
bags of what?
To fill a 3x3x3 hole, you first calculate the volume of the hole, which is 3 feet x 3 feet x 3 feet = 27 cubic feet. A 60-pound bag of concrete typically covers about 0.45 cubic feet. Therefore, to find out how many bags are needed, divide the volume of the hole by the coverage of one bag: 27 cubic feet ÷ 0.45 cubic feet/bag ≈ 60 bags. Thus, it would take approximately 60 bags of 60-pound concrete to fill the hole.
10 bags. Each 80 lb bag is 0.6 cubic feet, and your hole is 6 cubic feet.
That would depend on the density of the bags of topsoil.
20 bags. 16 oz are in a pound. 10 X 16 = 160 160/8 = 20
I don’t know
One pound is 16 ounces, so you can fill 2 8-ounce bags from each pound of mix. With 10 pounds of trail mix, you can fill 20 8-oz bags. Well, 19, since you're probably eating trail mix while you're filling the bags, and you'll have eaten one bag's worth while you worked.
To determine how many ten-pound bags of ice will fill a 48-quart cooler, we first need to convert quarts to pounds. A quart of ice weighs approximately 2.2 pounds, so a 48-quart cooler can hold about 105.6 pounds of ice (48 quarts x 2.2 pounds/quart). Dividing this by the weight of a ten-pound bag of ice, you would need about 10.56 bags, which means you would need 11 bags to fill the cooler completely.
To determine how many 80-pound bags of concrete are needed to fill a 55-gallon drum, first calculate the volume of the drum. A 55-gallon drum holds about 7.4 cubic feet (since 1 gallon is approximately 0.133 cubic feet). An 80-pound bag of concrete typically yields about 0.6 cubic feet. Therefore, you would need approximately 12 to 13 bags of concrete to fill the drum.
One pound is 16 ounces, so you can fill 2 8-ounce bags from each pound of mix. With 10 pounds of trail mix, you can fill 20 8-oz bags. Well, 19, since you're probably eating trail mix while you're filling the bags, and you'll have eaten one bag's worth while you worked.
There are about 2.3 7-ounce bags in one pound.
2.29 bags.