Three zeros... 39000
-0.312 = -312/1000 (since there are 3 digits after the decimal point, you divide by 1 followed by 3 zeros). Then simplify to -39/125
I think it is 39. Everyone keeps saying 39, but you would think a duodecillion would have twelve sets of three zeros after it. (a billion has three sets of three zeros, quadrillion has five sets of three). I think it is 13 * 3 = 39, but now I am going to go look it up.
none ========================== Another contributor qualified the first answer: The first answer is correct, except for 39, 48, 57, 66, 75, 84, and 93.
39 decimal places.
Three zeros... 39000
41duodecillion is a 1 followed by 39 zeros
six
-0.312 = -312/1000 (since there are 3 digits after the decimal point, you divide by 1 followed by 3 zeros). Then simplify to -39/125
A duodecillion is equal to 1 followed by 39 zeros in the short scale (American) numbering system. In the long scale (British) numbering system, a duodecillion is equal to 1 followed by 72 zeros. Therefore, in the short scale system, there are 39 zeros in a duodecillion.
One Astronomical Unit equals 149,598,000 kilometers.So 39 AU's equals, let's see- drop the three zeros, run it on the little calculator, add back the three zeros, and you get: 5,834,322,000 kilometers.(This only works with zeros!)
I think it is 39. Everyone keeps saying 39, but you would think a duodecillion would have twelve sets of three zeros after it. (a billion has three sets of three zeros, quadrillion has five sets of three). I think it is 13 * 3 = 39, but now I am going to go look it up.
Officially, it is between Undecillion at 36 zeros and Duodecillion at 39 zeros. So, a number with 38 zeros like IPv6 addresses at 3.40 x 1038 is 340 Undecillion
none ========================== Another contributor qualified the first answer: The first answer is correct, except for 39, 48, 57, 66, 75, 84, and 93.
There are an infinite number of them. But if you only count the whole numbers, then there are only 69 of them.
39
There are 2 significant figures in the measurement 230 kg. The zeros are not significant because they are placeholders.