(7*100*101)/2 = 35,350
jpacs
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What? How can there be 35,350 integers in the first 100 integers?
There are 14 of them.
There are 130 positive integers less than 1,000 that are divisible by seven but not divisible by 11
Of the 729 numbers that satisfy the requirement of positive integers, 104 are divisible by 7.
666 integers.
There are 544 positive integers less than 1,000 that are either divisible by two or by 11.
22 of them.
There are 130 positive integers less than 1,000 that are divisible by seven but not divisible by 11
Of the 729 numbers that satisfy the requirement of positive integers, 104 are divisible by 7.
There are 1,000 positive integers between 1,000 and 9,999, inclusive, that are divisible by nine.
666 integers.
There are 544 positive integers less than 1,000 that are either divisible by two or by 11.
22 of them.
6
Between 100 and 999 there are 448.
8 of them.
There are an infinite number of positive integers divisible by 3, 5, and 7. This is because there is no limit to numbers and they go on indefinitely in both a positive and a negative direction.
193 of them are divisible by one (or more) of the given numbers.
To find how many positive integers less than 100 are divisible by 3, 5, and 7, we first calculate their least common multiple (LCM). The LCM of 3, 5, and 7 is 105. Since 105 is greater than 100, there are no positive integers less than 100 that are divisible by all three numbers. Therefore, the answer is 0.