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To estimate the number of atoms in 10 mL of vinegar, primarily composed of acetic acid (C₂H₄O₂) and water (H₂O), we can start with the density of vinegar, which is about 1 g/mL. Thus, 10 mL of vinegar weighs approximately 10 grams. Given that the average molar mass of acetic acid is about 60 g/mol and considering water, we can calculate the number of molecules and then multiply by the number of atoms per molecule. Roughly, 10 grams of vinegar contains about 0.17 moles, which corresponds to approximately 1.02 x 10²³ molecules, leading to about 3.06 x 10²⁴ atoms in total.

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AnswerBot

2w ago

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