The number of bits in an integer is the number of times you can divide the integer by 2, truncating each result, before you reach zero.
There are 8 bits in a byte, so a two byte integer would be 16 bits. The largest 16 bit integer possible would be 11111111111111112, which is 65535 in base 10.
The largest integer is 211 - 1 which is 2048 - 1 = 2047
From -524287 to 524288
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The number of bits in an integer is the number of times you can divide the integer by 2, truncating each result, before you reach zero.
8 bits = 1byte 2 bytes = 1int dint (double integer) = 4bytes = 32bits
11 bits (which actually allows -1024 to 1023)
What is the decimal equivalent of the largest binary integer that can be obtained with (a) 11 bits and (b) 25 bits?
In computer programming, a variable can be (among other things) an integer or a long integer. An integer can be any whole number in the range of -32,768 to 32,767 A long integer can be any whole number in the range of -2,147,483,648 tp 2,147,483,647 I have never heard of an "integer" variable being called a "short integer" but it makes a kind of sense. Note: The size of integer types is platform-dependent, but usually: short: 16 bits int: 32 bits (16 in archaic systems: MSDOS OS Windows16) long: 32 bits (64 in unix64) long long: 64 bits
A 128-bit register can store 2 128th (over 3.40 × 10 38th) different values. The range of integer values that can be stored in 128 bits depends on the integer representation used.
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There are 8 bits in a byte, so a two byte integer would be 16 bits. The largest 16 bit integer possible would be 11111111111111112, which is 65535 in base 10.
2x-1
2x -1
The largest integer is 211 - 1 which is 2048 - 1 = 2047
65,535 in decimal = 1111111111111111 in binary.