If the bricks are in feet then 51/2 bricks would be needed.
no .of bricks = area of room /area of bricks area of room = 9 X12 X12 X12 inches ( 1 foot =12 inches ) area of bricks =3 X8 no.0f bricks =9 X12 X12 X12 inches /3 X 8 =648
216
10 x 7 or 70 square feet
The question, as stated cannot be answered. You need to know two dimensions of the bricks to find the area of each brick, convert that area into square feet (if necessary) and then divide 256 by the area of each brick. Bricks are not usually square so it would not be appropriate for me to assume that the bricks are 16" by 16".
-70
The answer will depend on the size of the bricks!
488 bricks.
10x7=70
Area to be covered = 5 ft*6 ft = 60 in*72 in = 4320 sq in. Area of each brick = 4 in* 10 in = 40 sq in. So, in theory, you will need 4320/40 = 108 bricks.
The answer will depend on the size of the bricks and the dimension of the area. 54 feet x 29 feet will require far fewer than 54 metres x 29 metres.
It depends on the dimensions used for the measurements of the bricks. If the bricks are 6 ft x 9 ft (and there is nothing in the question to indicate otherwise), then 6 bricks will be enough.
You need close to 800 bricks, figuring for some breakage.
648 Because: There are 12 inches in 1 foot. So 1ft wide is 3 bricks (12/4=3) and 1 ft long is 1.5 bricks (12/8 = 1.5). So 6ft x 3 = 18 bricks, 24ft x 1.5 = 36 bricks. To get the area: 36 bricks x 18 bricks = 648 Bricks.
how many bricks in 1m cube
115 should do it!
It is the same as 12 x 30 * 30 which is 8640.