the options i can see are: 1111111111 111111112 11111122 1111222 112222 22222 there are 6 combinations but i will need to reformulate to work out how many permutations of these 6 combinations there are
9
245
Well, isn't that a happy little riddle! If one of the coins is not a 10p coin, then it must be a 1p coin. So, you have a 10p coin and a 1p coin in your hand, making a total of 11p. Just like painting, sometimes it's the small details that make the big picture come together beautifully.
The simplest way is 2*10p
the options i can see are: 1111111111 111111112 11111122 1111222 112222 22222 there are 6 combinations but i will need to reformulate to work out how many permutations of these 6 combinations there are
10
Oh, what a happy little question! You can make one pound using different combinations of coins. You can use 100 one-penny coins, or 50 two-penny coins, or 20 five-penny coins, or 10 ten-penny coins, or 5 twenty-penny coins, or 2 fifty-penny coins. Just mix and match those coins and let your creativity shine!
9
245
Well, isn't that a happy little riddle! If one of the coins is not a 10p coin, then it must be a 1p coin. So, you have a 10p coin and a 1p coin in your hand, making a total of 11p. Just like painting, sometimes it's the small details that make the big picture come together beautifully.
how many ways to make 25p using 1p 2p 5p 10p 20 coins
two £0.05 + £0.05 = £0.10
There are several ways to make 15p using different combinations of coins. One way is to use one 10p coin and one 5p coin. Another way is to use three 5p coins. Additionally, you could use a combination of one 10p coin and five 1p coins. In total, there are multiple combinations that can add up to 15p.
150 10p coins.
To determine the number of combinations of coins that can make one pound, we must consider the various denominations of coins in circulation. In the British currency system, there are eight common coins: 1p, 2p, 5p, 10p, 20p, 50p, £1, and £2. To calculate the number of combinations, we can use a mathematical approach called the "coin change problem," which involves dynamic programming to efficiently compute the possible combinations. The exact number of combinations would depend on the specific constraints and parameters set for the problem.
There are 100 pence in one pound. Therefore, to find out how many 10p coins are needed to make one pound, you would divide 100 by 10, which equals 10. So, you would need 10 10p coins to make one pound.