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You can calculate that as follows: 85 - 15 - 1. If you want to include both endpoints (greater or equal to 15, less than or equal to 85), the calculation becomes 85 - 15 + 1. You can verify that this is correct, using smaller numbers - for example, "how many numbers are between 1 and 5".


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Q: How many counting numbers are there greater than 15 but less than 85?
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None of them. All counting numbers are either odd or even.


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How many two-digit counting numbers are greater than 70 or a multiple of ten?

- There are an infinite number of "counting numbers" that are greater than 70. - There are also an infinite number of "counting number" that are multiples of 10. So.... since you used an "OR" statement, this mean how many number are true for both statements above. That would be: AN INFINITE NUMBER of counting numbers. In fact, if you had said "AND", it still would be an infinite number: 80, 90, 100, ... and so on FOREVER. * * * * * The above answer has interpreted the questions as "two-digit counting numbers greater than 70" OR "a multiple of ten". Apart from the fact that there are not an infinite number of two-digit counting numbers greater than 70, the answer would be correct. But the answer could be interpreted as "two digit counting numbers" that are "greater than 70" OR "a multiple of ten". In that case, the first set is {71, 72, ... 99} and the second is {10, 20, 30, ... 90} with an intersection set consisting of {80 and 90} So there are 29 + 9 - 2 = 36 such number.


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