You can calculate that as follows: 85 - 15 - 1. If you want to include both endpoints (greater or equal to 15, less than or equal to 85), the calculation becomes 85 - 15 + 1. You can verify that this is correct, using smaller numbers - for example, "how many numbers are between 1 and 5".
None. All counting numbers are even or odd.
No- not exactly. Negative integers are not counting numbers. Positive integers are identified with counting numbers. Many authors like to start with zero as a counting number.
To find the two-digit counting numbers less than 30, we consider the numbers from 10 to 29, which gives us 20 two-digit numbers. The multiples of 20 that are two-digit numbers are 20. Since 20 is already included in the count of two-digit numbers less than 30, the total remains 20. Therefore, there are 20 two-digit counting numbers that are either less than 30 or a multiple of 20.
All numbers are either odd or even, none are both, so less than 30 there are 29 counting numbers that are either odd or even but not both. (Assuming you mean starting to count with 1.)
Five.
None of them. All counting numbers are either odd or even.
None. All counting numbers are even or odd.
858
Twelve numbers exactly are greater than 76 and less than 89.
The prime numbers that are greater than 80 and less than 100 are 83, 89, and 97.
14 of them.
3 composite numbers, 21, 22, and 24, are greater than 20 but less than 25.
There are 15 composite numbers greater than 50 but less than 70
Infinitely many.
it's 5
- There are an infinite number of "counting numbers" that are greater than 70. - There are also an infinite number of "counting number" that are multiples of 10. So.... since you used an "OR" statement, this mean how many number are true for both statements above. That would be: AN INFINITE NUMBER of counting numbers. In fact, if you had said "AND", it still would be an infinite number: 80, 90, 100, ... and so on FOREVER. * * * * * The above answer has interpreted the questions as "two-digit counting numbers greater than 70" OR "a multiple of ten". Apart from the fact that there are not an infinite number of two-digit counting numbers greater than 70, the answer would be correct. But the answer could be interpreted as "two digit counting numbers" that are "greater than 70" OR "a multiple of ten". In that case, the first set is {71, 72, ... 99} and the second is {10, 20, 30, ... 90} with an intersection set consisting of {80 and 90} So there are 29 + 9 - 2 = 36 such number.
No- not exactly. Negative integers are not counting numbers. Positive integers are identified with counting numbers. Many authors like to start with zero as a counting number.