The volume of a cylinder is pi * r^2 * height. For a 10 foot pipe with a 1 foot internal diameter (1/2 foot radius), the volume is: ~ 3.1416 * (.5)^2 * 10 = 7.854 cu. ft. of water (or anything else)
volume = pi * r 2* l = 3.1416*1.252 * 500 = 2454.375 cu ft 1 cu ft = 6.2288 imp gallon 2454.375 cu ft = 15287.811 gallons or say 15288.
There are 1.093611 cu. yds in a cu. m so a cubic metre is about 10% bigger than a cubic yard
10 x 10 x 2/3 ie 66.67 cu ft = 66.67/27 cu yds, call it 2-and-a-half.
As asked, the question is nonsense as:* millimeters are a measure of length; whereas* liters are a measure of volume.However, if you meant milliLITERS or CUBIC millimeters, then:1 l = 1000 ml→ 7.2 l = 7.2 x 100 ml = 7200 mlor:1 cm = 10 mm→ 1 cu cm = 1 cm x 1 cm x 1 cm = 10 mm x 10 mm x 10 mm = 1000 cu mm1 ml = 1 cu cm → 1 l = 1000 cu cm→ 1 l = 1000 x 1000 cu mm = 1000000 cu mm→ 7.2 l = 7.2 x 1000000 cu mm = 7200000 cu mm
This pipe has a volume of 24.5 cubic feet.
Copper (Cu) has one 3d electron.
1 liter = 10^-3 cu m 1nm = 10^-9 m 1 cu nm = 1 nm x 1 nm x 1 nm = 10^-9 m x 10^-9 m x 10^-9 m = 10^-27 cu m → 1 liter = 10^-3 ÷ 10^-27 cu nm = 10^24 cu nm = 1,000,000,000,000,000,000,000,000 cu nm.
10 m^3 = 353.147 cu ft.
The volume of a cylinder is pi * r^2 * height. For a 10 foot pipe with a 1 foot internal diameter (1/2 foot radius), the volume is: ~ 3.1416 * (.5)^2 * 10 = 7.854 cu. ft. of water (or anything else)
if the BUCKET is 12" dia at the top tapering to 10" and 10" deep it holds 950 cu/inches. A cu/yard is 46656 cu/inches so number of buckets is 49 (rounded up)
volume = pi * r 2* l = 3.1416*1.252 * 500 = 2454.375 cu ft 1 cu ft = 6.2288 imp gallon 2454.375 cu ft = 15287.811 gallons or say 15288.
3.4 mole Cu (6.022 X 10^23/1mol Cu ) = 2.047 X 10^23 atoms of copper.
how many cu ft is a yard
There are 1.093611 cu. yds in a cu. m so a cubic metre is about 10% bigger than a cubic yard
To find the weight of 4.6 x 10^25 atoms of copper, you can start by calculating the molar mass of copper, which is approximately 63.55 g/mol. Next, convert the number of atoms to moles by dividing by Avogadro's number (6.022 x 10^23). Finally, multiply the number of moles by the molar mass to find the weight in grams.
The cubic yards require that the width of the pile also be given. Assume the width of the pile of dirt, w , is 80 feet. V = ( L ) ( w ) ( h ) V = ( 300 ft ) ( 80 ft ) ( 10 ft ) = 240 x 10^3 cu ft V = ( 240 x 10^3 cu ft ) ( 1 cu yd / 27 cu ft ) V = 8889 cu yd <------------------