volume = area*length = Pi/4*(1.52)*20 feet*12inches = 424.115 cubic inches
424.115 / 1728 cu.in. = 0.2454 cubic feet
(0ne cu.ft. = 1728 cu.in.)
The volume of a cylinder is pi * r^2 * height. For a 10 foot pipe with a 1 foot internal diameter (1/2 foot radius), the volume is: ~ 3.1416 * (.5)^2 * 10 = 7.854 cu. ft. of water (or anything else)
volume = pi * r 2* l = 3.1416*1.252 * 500 = 2454.375 cu ft 1 cu ft = 6.2288 imp gallon 2454.375 cu ft = 15287.811 gallons or say 15288.
There are 1.093611 cu. yds in a cu. m so a cubic metre is about 10% bigger than a cubic yard
10 x 10 x 2/3 ie 66.67 cu ft = 66.67/27 cu yds, call it 2-and-a-half.
3.141579265
This pipe has a volume of 24.5 cubic feet.
Copper (Cu) has one 3d electron.
1 liter = 10^-3 cu m 1nm = 10^-9 m 1 cu nm = 1 nm x 1 nm x 1 nm = 10^-9 m x 10^-9 m x 10^-9 m = 10^-27 cu m → 1 liter = 10^-3 ÷ 10^-27 cu nm = 10^24 cu nm = 1,000,000,000,000,000,000,000,000 cu nm.
10 m^3 = 353.147 cu ft.
The volume of a cylinder is pi * r^2 * height. For a 10 foot pipe with a 1 foot internal diameter (1/2 foot radius), the volume is: ~ 3.1416 * (.5)^2 * 10 = 7.854 cu. ft. of water (or anything else)
if the BUCKET is 12" dia at the top tapering to 10" and 10" deep it holds 950 cu/inches. A cu/yard is 46656 cu/inches so number of buckets is 49 (rounded up)
volume = pi * r 2* l = 3.1416*1.252 * 500 = 2454.375 cu ft 1 cu ft = 6.2288 imp gallon 2454.375 cu ft = 15287.811 gallons or say 15288.
3.4 mole Cu (6.022 X 10^23/1mol Cu ) = 2.047 X 10^23 atoms of copper.
how many cu ft is a yard
There are 1.093611 cu. yds in a cu. m so a cubic metre is about 10% bigger than a cubic yard
.07 (No. That is incorrect.) Actually there are 27 cu ft in a cu yard or .037 cu yards in a cu ft.
To find the weight of 4.6 x 10^25 atoms of copper, you can start by calculating the molar mass of copper, which is approximately 63.55 g/mol. Next, convert the number of atoms to moles by dividing by Avogadro's number (6.022 x 10^23). Finally, multiply the number of moles by the molar mass to find the weight in grams.