Q: How many degree s are in a vertical angle?

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A regular pentagon has 5 sides and each interior angle measures 108 degrees not 172 degrees

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I think you mean 108 degrees (superscript "o" is often used for "degrees"). From another answer in this section, using s=number of sides=Number of angles, you get angle = 180(1 - 2/s) which can be turned around to 2/s = 1 - angle/180 or s=360/(180-angle) So for 108 degrees you get s=360/(180-108) which is 360/72 = 5 sides.

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body is projected with a velocity 3o m/s at an angle 30 degree with vertical find maximum height time of flight and range

128 degrees.An angle's supplement, when added to the original angle, will form a straight (180 degree) angle.

A regular pentagon has 5 sides and each interior angle measures 108 degrees not 172 degrees

The vertical component of the escalator's velocity at 45 degrees can be found by multiplying the given velocity (3 m/s) by the sine of the angle (sin 45° ≈ 0.7071). So the vertical component would be 3 m/s * 0.7071 ≈ 2.12 m/s.

The vertical velocity component of the ball can be found by multiplying the initial speed (31 m/s) by the sine of the launch angle (35 degrees). Vertical velocity = 31 m/s * sin(35) ≈ 17.7 m/s. The vertical velocity component is approximately 17.7 m/s.

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The vertical velocity at the top of the path of a projectile thrown straight up is 0 m/s because it momentarily stops before falling back down. For a projectile launched at an angle, the vertical velocity at the top of the path depends on the initial velocity and launch angle, but it will also momentarily be 0 m/s before changing direction.

The position vector of the raindrop can be expressed as the vector sum of two components: one due to its vertical motion and the other due to its horizontal motion. Given the velocity is 8 m/s at an angle of 30 degrees with the vertical, you can decompose this into vertical (8 * sin(30°) m/s) and horizontal (8 * cos(30°) m/s) components. By integrating these components over time, you can determine the position vector of the raindrop at any given point.

The acceleration in the vertical direction is due to gravity and is approximately 9.8 m/s^2 downward. The vertical acceleration remains constant throughout the ball's flight trajectory.

I think you mean 108 degrees (superscript "o" is often used for "degrees"). From another answer in this section, using s=number of sides=Number of angles, you get angle = 180(1 - 2/s) which can be turned around to 2/s = 1 - angle/180 or s=360/(180-angle) So for 108 degrees you get s=360/(180-108) which is 360/72 = 5 sides.

No , a parallelogram can not have a 90 Degree angle .Reason : A Parallelogram can be defined as a quadrilateral whose two s sides are parallel to each other and all the four angles at the vertices are not 90 degrees or right angles, then the quadrilateral is called a parallelogram.

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