A myriagon has 10,000 sides. The formula to calculate the number of diagonals in a polygon is ( \frac{n(n-3)}{2} ), where ( n ) is the number of sides. For a myriagon, substituting ( n = 10,000 ) gives ( \frac{10,000(10,000-3)}{2} = \frac{10,000 \times 9,997}{2} = 49,985,000 ) diagonals. Thus, a myriagon has 49,985,000 diagonals.
A myriagon, which is a polygon with 10,000 sides, has 10,000 lines of symmetry. This is because a regular myriagon, like other regular polygons, has a line of symmetry for each vertex, as well as for each side, resulting in a total equal to the number of sides. Thus, every vertex and side contributes to the symmetry, leading to the conclusion that a regular myriagon has 10,000 lines of symmetry.
It has 2 diagonals
It has 9 diagonals
4 diagonals
It has 5 diagonals
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45
i think is myriagon!!
Ten thousand, but more generally "lots".
A myriagon, which is a polygon with 10,000 sides, has 10,000 lines of symmetry. This is because a regular myriagon, like other regular polygons, has a line of symmetry for each vertex, as well as for each side, resulting in a total equal to the number of sides. Thus, every vertex and side contributes to the symmetry, leading to the conclusion that a regular myriagon has 10,000 lines of symmetry.
It has 1,345,890 diagonals
A undecagon has 44 diagonals. A dodecagon has 54 diagonals. An octagon has 20 diagonals. A heptagon has 14 diagonals.
24 diagonals
2 diagonals
It has 2 Diagonals!!!
There are 20 diagonals
It has 27 diagonals