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What is the number of sides of polygons which has 44diagonals?
11 sides The diagonal of a polygon is a line segment that joins two non adjacent vertices. So for a n-sided polygon, each vertex can be joined to n-3 other sides. So there ought to be n x (n-3) diagonals for a n-sided polygon; however, each diagonal is counted twice, once by the vertex at each end. So the number of diagonals is: diagonals = n (n-3) / 2 So for 44 diagonals: 44 = n (n-3) / 2 88 = n2 - 3n n2 - 3n - 88 = 0 (n - 11)(n + 8) = 0 n = 11 or -8 Since the number of sides can't be negative, the number of sides is 11, a hendecagon (or undecagon)
Is a perimeter of a rhombus with the side of 22 is 88?
The formula for the perimeter of a rhombus is fairly simple. The perimeter of an object is the sum of its sides. Since you specify a rhombus with four sides of 22, the sum of those sides would be 88.
What is the answer for 4n-16 equals 88?
4n-16 = 88 add 16 to both sides of equation 4n = 104 divide both sides by 4 n = 26
12x-28 equals 18x-88 what is x?
12x - 28 = 18x - 88Put the variables on one side and the constants on the other by subtracting 12x from both sides and adding 88 to both sides. 12x - 12x - 28 + 88 = 18x - 12x - 88 + 88 Simplify 60 = 6x Divide both sides by 6 x = 10 If you want to check your answer, which is always a good idea, plug in 10 for x in the original expression and see if you get a true statement: 12(10) - 28 = 18(10) - 88 120 - 28 = 180 - 88 92 = 92
How do you show work by doing a soliving equations problem 40-4n equals 88?
40- 4n = 88 SUBTRACT 40 from BOTH SIDES -4n = 48 multiply BOTH sides by -1 4n = -48 divide BOTH sides by 4 n = -12
