Octacontagon
If the polygon has n sides, it has n*(n - 3)/2 diagonals So, n(n - 3)/2 = 40 or n(n - 3)= 80 for which there is no solution. The question has no answer in terms of plane geometry.
80-5= 75
When the given vertices are plotted and joined together on the Cartesian plane they will form a 4 sided quadrilateral whose diagonals intercept each other at right angles and so multiplying the lengths of the diagonals divided by two will produce an area of 80 square units.
It depends on the shape of the area. It could be a perfect square or a sknny rectangle. The length would be affected by the shape.
alpdorigingon
An 80 sided shape is called a Octacontagon.
10 sided 2D shape is called a decagon 20 sided 2D shape is called a icosagon 30 sided 2D shape is a swimming pool 40 sided 2D shape is unknown 50 sided 2D shape is unknown 60 sided 2d shape is unknown 70 sided 2d shape is unknown 80 sided 2d shape is unknown 90 sided 2d shape is unknown 100 sided 2d shape is unknown 110 sided 2d shape is unknown 111 sided 2d shape is unknown 120 sided 2d shape is unknown 130 sided 2d shape is unknown
octacontagon is an 80-sided polygon
Octacontagon
If the polygon has n sides, it has n*(n - 3)/2 diagonals So, n(n - 3)/2 = 40 or n(n - 3)= 80 for which there is no solution. The question has no answer in terms of plane geometry.
80/5 = 16
80-5= 75
a regular octacontagon
Octacontogon is its real name. But, really, for any shape with a side number higher than ten, you can just append the suffix -gon to the number, i.e. 12-gon, 56-gon, et cetera.
When the given vertices are plotted and joined together on the Cartesian plane they will form a 4 sided quadrilateral whose diagonals intercept each other at right angles and so multiplying the lengths of the diagonals divided by two will produce an area of 80 square units.
Assuming it is an 80 sided REGULAR polygon, each exterior angle is 360/80 degrees = 4.5 degrees. So each interior angle = 180 - 4.5 = 175.5 degrees.