That depends what coins are allowed. Since I don't know in what country you live, there is really no way to know. For "n" different coins, you have "n" options where the same coin is used twice; you also have n(n-1)/2 options that use two different coins.
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Assuming that you are only using current US coins (5, 10, 25 and 50 cents), the answer is 21. NickelsDimesQuartersHalves1500013100112009300740055003600170010010811062104310241005105020312012205001310112010011
It depends on which country's currency the question is about.
Different countries use coins of different denomination so it is necessary to know which country the question is about. Butsince you have not bothered to provide that crucial bit of information, I cannot provide a more useful answer.
The single die can land in 6 different ways. For each of those . . . The first coin can land in 2 different ways. For each of those . . . The second coin can land in 2 different ways. Total number of different possible outcomes = (6 x 2 x 2) = 24 IF the coins have different colors so that you can tell them apart. If you can't tell the coins apart, then there are only 12 different outcomes.