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I will presume that you are using the space of integers (as there are in infinite number of real or even rational numbers between 1 and 15).
There are 15 integers on the interval of [1,15] and we want to find all possible combinations of 6 numbers from this set.
We use a combination, 6C15= 15! / (6! * (15 - 6)!) = 15! / (6! * 9!)
If you do not have a calculator which does factorials or combinations, then you can do some cancellations to make the computation a little easier:
15! = 15 * 14 * 13 * 12 * 11 * 10 * 9!
so we can cancel the 9!, which leaves us with:
15 * 14 * 13 * 12 * 11 * 10 / 6!
This is still going to involve the multiplication and division of very large numbers, so I took the pansy route and just used a calculator and got:
5,005 different possible combinations.
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What plus what equals 115?
To find out what plus what equals 115, we can set up an equation as x + y = 115. This equation represents two unknown numbers that add up to 115. To solve for x and y, we need more information or constraints. Without any additional context or constraints, there are infinite possible combinations of numbers that could add up to 115.
What prime numbers equal 115?
The prime numbers (factors) of 115 are: 5 and 23
What numbers are divisible by 115?
230 divided by 115 is 2.
What numbers equal 115?
There is only one known to modern science.Out of all the hundreds of numbers that have been discovered, 115 is the only one equal to 115.
How do you determine five numbers that have a mean of 23?
23*5 = 115 So pick any four numbers: integers, fractions, irrational numbers, whatever. Add them together to give a sum S. Let the 5th number be 115 - S Then: sum of all five numbers = (sum of the first four numbers) + (the fifth number) = S + (115 - S) = 115 And the count of numbers = 5 So mean = Sum/Count = 115/5 = 23
