Well, isn't that a happy little math problem! When a number is divided by another number, we get a quotient and a remainder. In this case, we are looking for natural numbers that leave a remainder of 5 when divided into 47. So, we start by listing some numbers that fit this description: 5, 10, 15, 20, 25, 30, 35, 40, and 45. That's 9 different numbers in total that will leave a remainder of 5 when divided into 47.
Chat with our AI personalities
Unless they are divided by themselves or one, they will always have a remainder.
49 can be divided by these numbers without leaving a remainder: 1 7 and 49.
57 can be divided by 3 and 19 with no remainder. 51 can be divided by 3 and 17 with no remainder.
Even numbers can be divided by 2 (with no remainder) while odd number can not be divided by 2 (with no remainder). 4 is an even number (2 into 4 goes twice) 5 is an odd number (2 into 5 goes twice with a remainder of 1)
even numbers are exactly divisible by two. ie. they do not give a remainder when divided by 2. natural numbers are positive integers starting from 1. even natural numbers are a combination of both.. eg. 2,4,50 etc the term positive is not required for these numbers because, natural numbers are positive !... so positive 'natural number' is like saying ' approximated estimate '..