There's no way of knowing which numbers satisfy all three conditions without knowing the third condition.
No. No number can be divisible by a number greater than it. 812 is greater than 6 so 6 cannot be divisible by 812.
80 is divisible by 5 and 4 and is greater than 75
Any of the infinite quantity of numbers between 50 and 60 is divisible by 9, but out of all of them, only 54 is evenlydivisible by 9.
No number meets these criteria. The number must be between 41 and 49. The only number in that range that is evenly divisible by 11 is 44, but 44 is even, not odd.
If the sum of its' digits are divisible by 3 for all numbers greater than 9.
9 is greater than 6 and divisible by 3.
No. No number can be divisible by a number greater than it. 812 is greater than 6 so 6 cannot be divisible by 812.
80 is divisible by 5 and 4 and is greater than 75
Any of the infinite quantity of numbers between 50 and 60 is divisible by 9, but out of all of them, only 54 is evenlydivisible by 9.
For example, for all numbers between 101-200: for (int i = 101; i
There are 67 numbers between 100 and 500 divisible by 6. The first number greater than 100 divisible by 6: 100 ÷ 6 = 16 r 4 → first number divisible by 6 is 6 × 17 = 102 Last number less than 500 divisible by 6: 500 ÷ 6 = 83 r 2 → last number divisible by 6 is 6 × 83 = 498 → all multiples of 6 between 17 × 6 and 83 × 6 inclusive are the numbers between 100 and 500 that are divisible by 6. → there are 83 - 17 + 1 = 67 such numbers.
None of them. Even numbers are divisible by themselves and 2. Every even number greater than two has at least two even factors..
No number meets these criteria. The number must be between 41 and 49. The only number in that range that is evenly divisible by 11 is 44, but 44 is even, not odd.
304
304
If the sum of its' digits are divisible by 3 for all numbers greater than 9.
No. To be divisible by a number it must be greater than, or equal to, that number. 10 is less than 66, so 10 cannot be divisible by 66.