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teshome hambissa

first space filled with A this implies that n(first)=1.

second space filled with all letters from a-z this implies that n(second)=26.

third space filled with all letters from a-z this implies that n(third)=26.

therefore by principle of counting

1x26x26=676.

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Q: How many different three-letter initials are there that begin with an A?
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