Q: How many different ways can 3 people be seated in 4 chairs?

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6 people multiplied by 6 different chairs meaning there are a total of 36 different combinations because each chair has 6 different combinations. - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Rafaelrz. If you have 6 chairs in a row, and 6 persons are going to be seated in those chairs, the number of different arrangements (permutations) the 6 people can be seated is 6! (six factorial): 6! = 6x5x4x3x2x1 = 720 i.e., The first person to sit has 6 options. For each option of the first person the second has 5 options. For each option of the second person the third has 4 options. And so on.

6 tables will be left out without atleast 1 person...

7 X 6 X 5 X 4 X 3 X2 X 1 = 5040 different ways that seven people can be seated in one row of seven people.

There are about 2 sensible reasons. You get 25 chairs tell the 25 people to sit. Tell them to sit on the floor.Answer:25 people can be seated in 25! ways (25! is factorial 25, or 25x24x22x21 ....x3x2x1) as the first chair can be filled in 25 ways, the second in 24, the third in 23 and so on. This comes to 1.5511210043 × 1025 different ways

group of 1,2,4,7,14,28 people per table

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6 people multiplied by 6 different chairs meaning there are a total of 36 different combinations because each chair has 6 different combinations. - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Rafaelrz. If you have 6 chairs in a row, and 6 persons are going to be seated in those chairs, the number of different arrangements (permutations) the 6 people can be seated is 6! (six factorial): 6! = 6x5x4x3x2x1 = 720 i.e., The first person to sit has 6 options. For each option of the first person the second has 5 options. For each option of the second person the third has 4 options. And so on.

140

89

4 people seated on a row may have 4! = 4x3x2x1 = 24 different ways to sit.

5 chairs x 5 people = 25 choices

6 tables will be left out without atleast 1 person...

7 X 6 X 5 X 4 X 3 X2 X 1 = 5040 different ways that seven people can be seated in one row of seven people.

1380 people can be seated but another 700 can stand as well!

Two people.

14,000

two

There are about 2 sensible reasons. You get 25 chairs tell the 25 people to sit. Tell them to sit on the floor.Answer:25 people can be seated in 25! ways (25! is factorial 25, or 25x24x22x21 ....x3x2x1) as the first chair can be filled in 25 ways, the second in 24, the third in 23 and so on. This comes to 1.5511210043 × 1025 different ways