2890
1140
To find the total number of pages in the book, we can break down the page numbering. The digits used for pages 1 to 9 (9 pages) total 9 digits. For pages 10 to 99 (90 pages), they use 2 digits each, contributing 180 digits. Since 35 digits are used in total, this means the pages range from 1 to 24. The calculation is as follows: pages 1-9 use 9 digits, and pages 10-24 (15 pages) use 30 digits (15 × 2), totaling 39 digits. Therefore, the book has 24 pages.
5329 , i think
numbersdigitstotal digits1to991910to99902180100to2251263378Total567
To number the pages of a book with 256 pages, you need 3 different digit counts: 1-digit pages (1 to 9), 2-digit pages (10 to 99), and 3-digit pages (100 to 256). The 1-digit pages (1-9) require 9 digits, the 2-digit pages (10-99) require 90 pages × 2 digits = 180 digits, and the 3-digit pages (100-256) require 157 pages × 3 digits = 471 digits. Adding these together gives a total of 9 + 180 + 471 = 660 digits needed.
There are exactly 320 pages in 852 digits.
1140
To find the total number of pages in the book, we can break down the page numbering. The digits used for pages 1 to 9 (9 pages) total 9 digits. For pages 10 to 99 (90 pages), they use 2 digits each, contributing 180 digits. Since 35 digits are used in total, this means the pages range from 1 to 24. The calculation is as follows: pages 1-9 use 9 digits, and pages 10-24 (15 pages) use 30 digits (15 × 2), totaling 39 digits. Therefore, the book has 24 pages.
There are 116 1s in the first 1000 digits of pi.
There are 9 pages that use a single digit (pages 1-9), leaving 495 digits - 9 pages × 1 digit/page = 486 digits There are 90 pages that use 2 digits (pages 10-99), leaving 486 digits - 90 pages × 2 digits/page = 306 digits There are 900 pages that use 3 digits (pages 100-999); this would be 2,700 digits, so the number of pages is somewhere in the hundreds. 306 digits ÷ 3 digits/page = 102 pages in the hundreds. → total number of pages = 102 + 90 + 9 = 201 pages.
315
10 digits.
There are 9 pages with a single digit (pages 1-9) = 9 digits There are 30 - 9 = 21 pages with two digits = 21 × 2 = 42 digits → There are 9 + 41 = 51 digits in total.
642
5329 , i think
numbersdigitstotal digits1to991910to99902180100to2251263378Total567
To number the pages of a book with 256 pages, you need 3 different digit counts: 1-digit pages (1 to 9), 2-digit pages (10 to 99), and 3-digit pages (100 to 256). The 1-digit pages (1-9) require 9 digits, the 2-digit pages (10-99) require 90 pages × 2 digits = 180 digits, and the 3-digit pages (100-256) require 157 pages × 3 digits = 471 digits. Adding these together gives a total of 9 + 180 + 471 = 660 digits needed.