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using the formula 2^(m-1) -1 we can see that by setting 5 to be m we have :

2^(5-1) -1

=2^4 -1

=16-1

=15

and 15 /5 is 3 so we have 3 bit patterns

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Ayabongwa Nonjabulo

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Q: How many distinct 5-bit patterns?
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