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∙ 11y ago96 divisors.
They will take the form 2a*11b*13c*17d*19e
where a = 0, 1, 2, ... 6 and b, c, d, e can be 0 or 1.
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∙ 11y ago352 has 12 positive divisors: 1, 2, 4, 8, 11, 16, 22, 32, 44, 88, 176, 352.
The divisors of 121 are: 1, 11, 121.
No. 77 is not a prime number because it has more than two distinct divisors. 77 = 1 * 77 77 = 7 * 11
The divisors of 22 are: 1, 2, 11, 22.
First, you want to know the definition of a perfect number: A perfect number is an integer which is equal to the sum of all its positive integer divisors that are less than itself. Example: The positive integer divisors of 6, less than 6, are 1, 2, and 3. The sum of those divisors is 1 + 2 + 3 = 6. Therefore, 6 is a perfect number. Now, 21 does not meet this definition and therefore is not a perfect number. Let's try it. There are three positive divisors of 21, namely, 1, 3, and 7, that are less than 21, itself. (There are no others.) But the sum of these divisors is 1 + 3 + 7 = 11, which is not equal to 21. Therefore, we confirm that 21 is not a perfect number.
Prime squares have three factors. There are 11 of them in that range.
2. That is the only one. And the 11 divisors are 2k where k = 0, 1, ,2, ... , 10
352 has 12 positive divisors: 1, 2, 4, 8, 11, 16, 22, 32, 44, 88, 176, 352.
2,013 has 8 divisors: 1 3 11 33 61 183 671 2013.
Since 11 is a prime number, its only divisors are 1 and itself.
The divisors of 121 are: 1, 11, 121.
1, 11
No. 77 is not a prime number because it has more than two distinct divisors. 77 = 1 * 77 77 = 7 * 11
The divisors of 22 are: 1, 2, 11, 22.
The divisors of 99 are: 1, 3, 9, 11, 33, 99.
99 has six divisors: 1, 3, 9, 11, 33, 99.
22 has four divisors (also called factors): 1, 2, 11, 22.