Just the one: 2
Seven distinct factors.
7 factors. They are: 1, 2, 4, 8, 16, 32, 64
Not two DISTINCT prime factors, no. For example, 64 = 2^6 only has prime factor 2. All even numbers which are not a power of 2 must have at least two distinct prime factors, however; one of them will, of course, be 2.
64 and 96 have the longest prime factorizations in that range. If you're asking about distinct prime factors, quite a few are tied with three.
64 has only one prime factor: 2
Seven distinct factors.
If you're asking about distinct prime factors, there are eight numbers tied with three of them. If not, 64 has six twos.
If you're asking about distinct prime factors, there are eight numbers tied with three of them. If not, 64 has six twos.
7 factors. They are: 1, 2, 4, 8, 16, 32, 64
Not two DISTINCT prime factors, no. For example, 64 = 2^6 only has prime factor 2. All even numbers which are not a power of 2 must have at least two distinct prime factors, however; one of them will, of course, be 2.
Oh, dude, the positive difference between the number of distinct prime factors of 15 squared (225) and 64 cubed (262,144) is like 4. Prime factors are like those VIP numbers that can't be divided by anything except 1 and themselves. So, 225 has 2 distinct prime factors (3 and 5), and 262,144 has 1 distinct prime factor (2). Subtract 1 from 2, and you get 1. Wow, math can be fun, right?
The only prime factor of 64 is 2.
64 and 96 have the longest prime factorizations in that range. If you're asking about distinct prime factors, quite a few are tied with three.
64 = 2x2x2x2x2x2
64 has only one prime factor: 2
Prime factors of 64 are 26 (2x2x2x2x2x2)
The only prime factor of 64 is 2.