16 x 9 x 5 x 7 = 24 x 32 x 51 x 71
So it has (4 + 1) x (2 + 1) x (1 + 1) x (1 + 1) = 5 x 3 x 2 x 2 = 60 divisors.
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The divisors of 35 are: 1, 5, 7, 35.
numbers 1, 2, 3, 4, 5, 8, 16 are divisors number 16 numbers 1, 2, 3, 4, 5, 6, 10, 20 are divisors number 20 numbers 1, 2, 3, 4, 6, 8, 12, 24 are divisors number 24 numbers 1, 2, 3, 4, 7, 12, 28 are divisors number 28 next number is 32 and divisors are 1, 2, 4, 8, 16, 32
Since 7 is a prime, its only divisors are 1 and 7.
1, 2, 4, 5, 7, 8
1, 2, 3, 4, 5, 6, 7