Between 1 to 100 there will be: 8,18,28,38,48,58,68,78,80,81,82,83,84,85,86,87,88,89 & 98: total 20 eights. This will be true for all the other sets of 100 barring 800 to 899 which will have an additional 100 eights. So the answer will be 20 * 10 + 100 = 300.
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Ten eights times eight tenths is 1.
There are 20 eights between 1 and 100. To find this, we consider the units place and the tens place separately. In the units place, there are 10 eights (8, 18, 28, 38, 48, 58, 68, 78, 88, 98). In the tens place, there are also 10 eights (80, 81, 82, 83, 84, 85, 86, 87, 88, 89). Therefore, there are a total of 20 eights between 1 and 100.
37 and 1/2
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In 1 there are 8 eights. So 40 * 8 = 320. So there 320 eights in 40.
1
1/8 x 100% = 12.5%
1
8-(8/8) = 7 This is an example of a mathematical diversion where all numbers between 1 and 100 are to be constructed from three eights (or any other number) 1=(8/8)8 2= (8+8)/8 and so on
There are exactly 20 Nines. 9,19,29,39,49,59,69,79,89,90,91,92,93,94,95,96,97,98 which totals 18 and the last number 99 has 2 nines and therefore 20 nines in total.