The only thing that can be said that there must be at least 4 faces and at least 6 edges and that the polyhedron must satisfy the Euler criterion which requires that:
Faces + Vertices = Edges + 2.
8 edges and 5 faces
If it is a polyhedron, then four or more faces and four or more corners.
cylinder
The numbers in the question do not satisfy the Euler characteristic so there cannot be such a [convex] polyhedron.
It has 6 faces, 12 edges and 8 corners or vertices
6 faces, 12 edges
The faces in a 3-D shape (polyhedron, for example) are bordered by edges.
8 edges and 5 faces
A polyhedron is any 3D solid (such as a cube) - therefore, it can have any number of faces.
If it is a polyhedron, then four or more faces and four or more corners.
Well, honey, that sounds like a hexagonal prism to me. It's got those six faces, six vertices, and ten edges, making it the life of the 3D shape party. So, go ahead and strut your stuff with that hexagonal prism knowledge!
A tetradecachedron is a polyhedron, also known as a 14-sided polyhedron or 14-faced polyhedron. It is a convex solid with 14 faces, 24 edges, and 14 vertices. The term "tetradecachedron" can refer to any 14-faced polyhedron, not necessarily a specific shape.
cylinder
Actually, there is such thing as a polyhedron. Its a 3D shape and it's faces are all the same shapes. Doesn't matter what shape, actually. ^^^ ok, to the dude who answered before me (above): you're a butt... you didn't answer the freaking question! Its 6
A cube has 6 faces
The numbers in the question do not satisfy the Euler characteristic so there cannot be such a [convex] polyhedron.
It has 6 faces, 12 edges and 8 corners or vertices