1 ft = 16 in 1.5 ft = (1.5 x 16) in = 24 in Since the time is the same ( 1 min), then 1.5 ft/min equals to 24 in/min.
It will have descended 3000 ft.
10560 fpm
First, convert 20mph to ft/sec. (20 * 5280) ÷ 3600 = 28.9333... ft/sec To find out how long it would take to travel 500 ft, divide 500 by 28.9333.. and you get 17.28 seconds
(60 mi/hr) x (5,280 ft/mi) x (1 hr / 60 min) x (1 meter / 3.28084 feet)= (60 x 5,280) / (60 x 3.28084) (mi - ft - hr - meter / hr - mi - min - ft)= 1609.344 meters/minute
about 6075-ft (rounded)
Since one mile is equal to 5,280 feet, multiply 0.07 by 5,280. You will get 369.6 ft/h, but since you want feet per minute, divide 369.6 by 60. Your answer is 6.16 feet per minute.
47 ft per min times 4 min = 188 ft.
157/360 ft/sec = 0.436 ft/sec
i know there is , but i just dont know the name of the spider.
1 ft = 16 in 1.5 ft = (1.5 x 16) in = 24 in Since the time is the same ( 1 min), then 1.5 ft/min equals to 24 in/min.
That depends upon for how long it is moving:Every day it will travel 50 miles/hr x 5280 ft/mile x 24 hr/day = 6336000 ft/dayEvery hour it will travel 6336000 ft/day ÷ 24 hr/day = 264000 ft/hrEvery minute it will travel 264000 ft/hr ÷ 60 min/hr = 4400 ft/minEvery second it will travel 4400 ft/min ÷ 60 sec/min = 731/3 ft/sec ≈ 73.33 ft/sec* Added - The simple formula that should be used is converting MPH to feet per second (FPS). This is done by multiplying by 1.467, or for an easy rough estimate, 1.5. This result in 50mph = 73.35 fps. This is the method most often used by engineers and accident investigators. This can be used for determining braking distances for a car as well, once the deceleration rate is identified.
200 ft per 40 minutes 5 feet per minute 1 inch per second 0.0568 mile per hour (rounded)
30,000-40,000 ft
800×200=
65 mph equates to 5,720 ft/min
There are 60 minutes in an hour, so the toy travels for (5 feet / hour) * (60 minutes / hour) = 300 ft / hour.There are 3 feet in a yard, so the toy travels (300 ft / hour) * (1 yd / 3 ft) = 100 yards in one hour.