The answer depends on the length AND the cross-section of the pipe. Just one of the two measures is not enough.
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38.961039
1,770 gallons 10x10x3x5.9=
Length = 30*12 = 360 inches.Area = Pi/4*(dia2) = 0.785398*100 = 78.5398 square inchesVolume = 78.5398*360 = 28,274.3339 cubic inchesUS gallon = 231 cubic inches28,274.3339 / 231 = 122.3997 US gallons.
A round pool 30 feet wide and 52 inches deep can hold a maximum of 22,700 gallons of water.
There is no obvious reason why there should be any water in the pipe. Furthermore, there are no units associated with the width of the pipe, so its volume cannot be calculated.