It is 1692 US gallons, approx.
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If the diameter (from edge to edge) is 24 feet, then the volume is pi*(Dia/2)²*depth. First get everything into feet, so 52 in = 4 1/3 feet, then we have (12 ft)²*(4 1/3 ft)*pi = 1960.354 ft³. Next, 1 cubic foot = 7.4805 gallons, so it's 14664.43 gallons.
If the ratio of thicness to dia of cylinder is 0.1 and less, it is thin. And if this ratio is more than 0.1 it is thick cylinder
In order to calculate the volume of the pool, the depth must be known. Then the volume must be multiplied by the number of gallons of water per cubic foot. The surface area of an 18-ft-diameter pool is 254.47 sq ft. Multiply that number by the depth (in ft) to find the volume. Then multiply the volume by 7.481 (gallons per cu ft) to find how many gallons the pool will hold. Example, 18-ft-dia pool x 3 ft deep 254.47 x 3 = 763.41 cu ft 763.41 x 7.481 = 5711 gallon capacity
unit weight = 10.68 (outer dia. of pipe - thickness of pipe) x thickness of pipe unit will be 'lbs/foot' 1 lbs = 0.45359237 kg and 1 foot = 0.3048 meter or 1 meter = 3.2808 feet
Circumference of circle: 20 × π = 62.832 feet rounded to 3 decimal places