Type your answer here... 39 x 23 x 21 = 18,837 cubic inches
There are 1728 cu in in cu ft
18837/1728 = 10.9 cu ft
there are 7.48 gals in cubic foot
7.48 * 10.9 = 81.5 gallons
Need the length of the tank also to determine the amount of oil
21 inches of water in a round pool that is 27 feet 3 inches across is about 7,667 gallons.
The tank has a maximum holding capacity of 25.45 gallons US. Filled to within 2" of the top it will hold 22.9 gallons US. For your future reference the calculation is " length in inches x width in inches x height in inches divided by 231.
A cylinder with a radius of 21 inches and a height of 98 inches has a volume of 135,773.35 cubic inches. This cylinder would have a volume of 587.763 US gallons.
21 cubic feet = 36,288 cubic inches = 1571/11 gallons
A tank of 21 inches wide, 8 inches deep and 59 inches long will hold 36 gallons of gas. These gallons refers to US gallons.
Need the length of the tank also to determine the amount of oil
Making the assumptions that these measurements are in inches, and that the fish tank is a perfect cuboid, the volume of the fish tank is 49 x 19 x 21 = 19,511 cubic inches.Rounded to two decimal places, this is equal to 70.47 gallons.
21 gallons
21 gallons
21 gallons It is 25 gallons.
To find the volume of the fish tank in cubic inches, multiply the dimensions: 20 x 18 x 21 = 7560 cubic inches. To convert cubic inches to gallons, divide by 231 (since 1 gallon = 231 cubic inches). Therefore, a fish tank measuring 20 x 18 x 21 inches would hold approximately 32.8 gallons.
im no expert but it sounds like 125 For the size in gallons for a rectangular aquarium, the formula is: (Length x Width x Height) divided by 231
If the measurements are inches than the answer is 130 gallons (126.54 with greater accuracy than the 2 significant figures given in the dimensions)
It will hold 157.1 gallons of liquid.
21 US gallons
abt. 56.7 gallons (US)