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How many gallons of water does it take to fill a swimming pool that is 18' round and 54 deep?
70
How many gallons of a 80 percent solution must mix with 70 gallons of 10 percent solution to get 70 percent solution?
420 gallons. Here's how to find it; If X = Gallons of 80% mix, 0.8*X + 0.1*70 = 0.7*(X+70) Which we can then solve, 0.8X + 7 = 0.7X + 49 0.1X = 42 X = 420
How many gallons of a 60 percent antifreeze solution must be mixed with 70 gallons of 30 percent antifreeze to get a mixture that is 50 percent antifreeze?
Suppose G gallons are required. G gallons @ 60% implies 0.60*G gallons of the active ingredient. 70 gallons @ 30% implies 70*0.3 = 21 gallons of the active ingredient. This makes a total of (G + 70) gallons containing (0.6G + 21) gallons of active ingredient. The mixture is (0.6G + 21)/(G + 70) which is to be 50% or 0.5 So 0.6G + 21 = 0.5G + 35 or 0.1G = 14 which gives G = 140 gallons
How large is 70 cubic meters?
Well, as an example, a 70-cubic meter container could hold up to about 18,500 gallons of water.
How many gallons of a 70 percent solution must be mixed with 70 gallons of 10 percent antifreeze to get a mixture that is 60 percent antifreeze?
Say x = total gallons of solution at 60%Say y = gallons of 70% solutionx=70+y gallonsThen .60x = .70y + .1(70)substituting for x gives.60(70) + .60y = .70y + .1(70) or42 + .6y = .7y + 7 or42-7 = .1y gives y = 350 gals and x = 420 gals total solutionThe answer is 350 gallons
