How many gallons is a 33 feet round by 4 feet deep swimming pool?

Answer 1

A pool with diameter (the distance across at its widest point) equal to 33 feet and with a consistent depth of 4 feet holds 25,592.29 gallons of water. The volume (V) of the pool can be expressed as: V = pi*1/2 diameter squared*depth Or in this case: V = pi*16.5 feet squared*4 feet = 3.14159*272.25 feet squared*4 feet = 3421.1915 cubic feet One gallon of water equals .133681 cubic feet. 3421.1915 cubic feet of pool divided by .133681 cubic feet per gallon equals 25,592.29 gallons to fill the pool.