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A pool with diameter (the distance across at its widest point) equal to 33 feet and with a consistent depth of 4 feet holds 25,592.29 gallons of water. The volume (V) of the pool can be expressed as: V = pi*1/2 diameter squared*depth Or in this case: V = pi*16.5 feet squared*4 feet = 3.14159*272.25 feet squared*4 feet = 3421.1915 cubic feet One gallon of water equals .133681 cubic feet. 3421.1915 cubic feet of pool divided by .133681 cubic feet per gallon equals 25,592.29 gallons to fill the pool.

Q: How many gallons is a 33 feet round by 4 feet deep swimming pool?

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6015.77 gallons

It is 30.6 cubic feet = 190.3 Imperial gallons.

About 17,950 gallons.

28 is the diameter of the pool and 4 is the height (depth). 1 cubic foot is approx. 7.48 gallons. A round swimming pool is a cylinder. So: pi x (28/2)2 x 4 = 2463 cubic feet, multiply by 7.48 = 18423.24 gallons

1,770 gallons.

Related questions

6015.77 gallons

It is 30.6 cubic feet = 190.3 Imperial gallons.

A round swimming pool 12 feet across by 4 feet deep will hold 452 ft3 which converts to 3,381 gallons

'bout 1500 to 2000

About 17,950 gallons.

21 foot what? Radius, diameter or circimference? Presumably 4 feet deep?

how many gallons of water does a swimming pool 15 feet by 4 feet deep hold

28 is the diameter of the pool and 4 is the height (depth). 1 cubic foot is approx. 7.48 gallons. A round swimming pool is a cylinder. So: pi x (28/2)2 x 4 = 2463 cubic feet, multiply by 7.48 = 18423.24 gallons

3,398.4 gallons.

5,974 gallons.

1,770 gallons.

9,440 gallons.