You have to find the area of end of the tank occupied by the fluid. First, the area of one end of the tank is
3.14159 x (13/2)^2 = 132.7 ft^2
If you draw two lines, on one end of the tank, from the center of the tank to the intersection of top of the fluid at the circumference of the tank, the length of each line is equal to the radius of the tank (6.5'). A perpendicular line drawn from the center to the fluid level line, is the tank radius - fluid depth = 6.5' - 3.5' = 3.0'. The angle between the vertical line and one of radius lines to the edge of the liquid, is
ACOS(3.0 / 6.5) = 62.51 deg.
The angle between both of the first two lines drawn to each edge of the liquid is 2 x 62.51 deg = 125.03 deg. The area of this section that looks like a piece of pie, is
132.7 ft^2 x 125.03 / 360 = 46.1 ft^2.
1/2 of the length of the top of fluid line on the end of the tank is
square-root(6.5^2 - 3.0^2) = 5.77 ft
Of the pie-shaped piece, the area of the triangular portion that is not wetted by fluid is
3.0' x 5.77' = 17.3 ft^2.
The area of the wetted end of the tank therefore is the pie-shaped area minus the non-wetted trianglular area =
46.1 ft^2 - 17.3 ft^2 = 28.8 ft^2.
The volume of the fluid is the area of the wetted end x length =
28.8 ft^2 x 28 ft = 806.1 ft^3.
Since there are 7.48 gal / ft^3, total volume in gallons =
806.1 ft^3 x 7.48 gal/ft^3 = 6,029 gal
If the pool were filled all the way to the top it would hold 4,551.4 gallons of water. However this is generally not recommended. If filled to within 6 inches of the top (3.5 ft) it would hold 3,976 gallons.
You need more information. It all depends on the size of the cylinder
If it's a circular pool and 24 is the diameter and 4 is the depth then about 1,808.64 gallons of water would fit.
Diameter = 5 ft therefore radius = 2.5 ft. Height = 16 ft. 7.5 gallons = 1 cubic ft. Volume of a cone = 1/3*pi*radius2*height Volume = 1/3*pi*2.52*16 = 104.7197551 cubic feet Gallons of water in the tank = 7.5*104.7197551 = 785.3981634 gallons There are 785 gallons of water in the tank correct to three significant figures.
If filled, 2 gallons.
It Should Contain 72 Gal 43 Oz.
Filled to the top, this well would hold about 956 gallons of water.
If the pool were filled all the way to the top it would hold 4,551.4 gallons of water. However this is generally not recommended. If filled to within 6 inches of the top (3.5 ft) it would hold 3,976 gallons.
You need more information. It all depends on the size of the cylinder
Assuming that the pool diamater diminishes 1 foot for each foot of height, and the pool is filled to the top, the total capacity would be about 6439 gallons.
The amount of LPG in a cylinder can vary depending on its size and capacity. Typically, a standard 20-pound cylinder can hold up to 4.7 gallons (20 pounds) of LPG when filled to 80% capacity.
Depends on the depth. If it is 4 feet deep and it is cicular with a diameter of 24 feet then you have approx. 13,553 gallons of water. If it is 3 feet deep then you have approx. 10,152 gallons of water.
The gas in the liquified state under pressure and it can be filled inside the cylinder. Then it takes the entire available place in side the cylinder. This way gas filled in side the cylinder.
An empty cylinder weighs less because it contains only the weight of the cylinder itself, whereas a filled cylinder contains the weight of both the cylinder and the substance inside it. The substance inside adds to the total weight of the filled cylinder.
If it's a circular pool and 24 is the diameter and 4 is the depth then about 1,808.64 gallons of water would fit.
A 56-gallon propane tank typically measures around 24 inches in diameter and 44 inches in height. It can hold up to 420 pounds of propane when filled to 80% capacity.
Diameter = 5 ft therefore radius = 2.5 ft. Height = 16 ft. 7.5 gallons = 1 cubic ft. Volume of a cone = 1/3*pi*radius2*height Volume = 1/3*pi*2.52*16 = 104.7197551 cubic feet Gallons of water in the tank = 7.5*104.7197551 = 785.3981634 gallons There are 785 gallons of water in the tank correct to three significant figures.