answersLogoWhite

0

There are no gallons of water at all in a pool which is 18 feet by 48 inches deep. In order to contain something, you need three dimensions, not just two.

However, let's assume that you meant a round pool with a diameter of 18 feet and a depth of 48 inches. That pool would contain 7614.23499 gallons.

The radius equals the diameter / 2.

The area of such a pool is pi * radius squared.

The volume of the pool is the area * depth.

Radius = 18 feet / 2 = 9 feet

Area = 3.14159 * 9 feet * 9 feet = 254.46879 feet squared (or square feet)

Volume = 254.46879 feet squared * 4 feet = 1017.87516 feet cubed (or cubic feet)

One liquid gallon is defined as 0.133 680 555 cubic feet (Authorized tables, U.S. Code, Title 15, ch. 6, subchapter I, sec. 205, accessed 19 July 2008.)

Therefore,

1017.87516 cubic feet * (1 gallon / 0.133 680 555 cubic feet) = 7614.23499 gallons

User Avatar

Wiki User

15y ago

Still curious? Ask our experts.

Chat with our AI personalities

BeauBeau
You're doing better than you think!
Chat with Beau
RafaRafa
There's no fun in playing it safe. Why not try something a little unhinged?
Chat with Rafa
EzraEzra
Faith is not about having all the answers, but learning to ask the right questions.
Chat with Ezra

Add your answer:

Earn +20 pts
Q: How many gallons of water in a pool 18 feet by48 inches deep?
Write your answer...
Submit
Still have questions?
magnify glass
imp