12,345 gallons
A round pool with a 10-foot diameter and a 3-foot depth can hold up to 1,762 gallons of water.
Volume = pi*52*10 = 785.398 cubic feet to 3 decimal places
It depends how deep it is.
7500
1346 gallons
A round pool with a 10-foot diameter and a 3-foot depth can hold up to 1,762 gallons of water.
Volume = pi*52*10 = 785.398 cubic feet to 3 decimal places
It depends how deep it is.
367.012987 gallons
897.662 gallons in this pond.
A tank this size can hold a maximum of 3,590.65 US gallons of water.
7500
This pond can hold up to 1,436.26 gallons of water.
This cannot be answered as stated. There must be three dimensions given: width/depth/height. Or we must assume that the tank is "circular." More accurately, we assume the tank is a cylinder that is four feet high and 10 feet in diameter. The volume of a cylinder is given by the formula V = (Pi)r2h, where ris the radius of the base of the cylinder and h is its height. Since the radius is half the diameter, we get: V = (Pi) * (52) * 4 = 3.141 x 25 x 4 = 314.1 cubic feet of water. The question asked for the volume in gallons, however. One cubic foot of water contains about 7.48 gallons. So 314.1 x 7.48 = 2349.9 gallons.
If it is a round pool that is 10 feet wide and has 3 feet of water then it contains 1,770 gallons of water.
1346 gallons
It is: diameter = 31.4/pi which is about 10 units