Oh, dude, you're hitting me with the math questions now? Okay, so first we gotta find the volume of that space, which is 20 x 10 x 4 = 800 cubic feet. Then we convert that to gallons, which is like 7.48 gallons per cubic foot, so it's 800 x 7.48 = 5984 gallons. So yeah, that space would hold about 5984 gallons. Cool, right?
11,669.61 (rounded)
13,464.94 US gallons.
29,610.94 gallons (rounded)
2937.6 Gallons. Here's how. Volume = (area of base) x (height).Area of a circle is Pi * (radius squared). Radius is half of diameter = 10 ft/2 = 5 ft.Take pi = 3.1416, so 3.1416*(5 ft high)*(5 ft)2 = 392.7 ft3. 1 ft3 = 7.48052 gallons. 392.7 ft3 * 7.48052 gal/ft3 = 2937.6 gallons
10 .863 gallons
11,669.61 (rounded)
13,464.94 US gallons.
4745 gallons Best estimate I have.
Approx 4892 Imperial gallons.
There are 907.9202769 feet2 of water, but you will have to convert that into gallons.
29,610.94 gallons (rounded)
need to know the width of the tub as well.
2937.6 Gallons. Here's how. Volume = (area of base) x (height).Area of a circle is Pi * (radius squared). Radius is half of diameter = 10 ft/2 = 5 ft.Take pi = 3.1416, so 3.1416*(5 ft high)*(5 ft)2 = 392.7 ft3. 1 ft3 = 7.48052 gallons. 392.7 ft3 * 7.48052 gal/ft3 = 2937.6 gallons
To hold 550.0 gallons, you need a container with a volume of at least 550 gallons. Since there are 7.48 gallons in one cubic foot, the container would need to be approximately 73.5 cubic feet (550 ÷ 7.48). If you're considering the dimensions, a container that is 3 feet wide, 3 feet long, and about 6.1 feet high would suffice. Always consider a little extra capacity for overflow or expansion.
10 .863 gallons
201.97 US gallons == Mer om kalkylatorn.
By my calculations (and they could be wrong--English major here), it would hold 11,320 gallons. Volume = πr2h = π(45.040848895006380022594105034422)2(40)