There are 28 pairs in all the numbers between 1 and 8 (1&2,1&3, etc.)
2 groups of 16, 4 groups of 8, 8 groups of 4, 16 groups of 2. Not really divided or in groups, but there could be 1 group of 32 or everyone by themselves.
6.4
2 groups
If the 8 people consist of 6 or more women, the answer is none. If the question is intended to be gender neutral, then the answer is 8*7*6/(3*2*1) = 56
2
they can be 2 groups of 16, 4 groups of 8, 8 groups of 4, or 16 groups of 2
8 groups of 2 = 8 groups_of_2 × 2 items/group_of_2 = 16 items → 16 items ÷ 4 items/group_of_4 = 4 groups of 4.
There are 247 groups comprising 2 or more students.
There are five ways to do this, if you include 32 'groups' with one member each.The others are 2 groups of 16, 4 groups of 8, 8 groups of 4 and 16 groups of 2.
32
8 groups of 5 are there in 40.
56 will split into the following groups... 56 groups of 1 28 groups of 2 14 groups of 4 7 groups of 8 8 groups of 7 4 groups of 14 2 groups of 28 and 1 group of 56
She can have 1 group of 40, 2 groups 0f 20, 4 groups of 10, 8 groups of 5, 5 groups of 8 10 groups of 4, 20 groups of 2 or 40 groups of 1. This assumes that you don't want any partial books in any of your groups.
8
The answer is 8C6 = 8!/[6!*(8-6)!] where n! = 1*2*3*...*n So, the answer is 28.
4 groups of 10 = 40. 40 /5 = 8 so the answer is 8 groups of 5.
8