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How many handshakes will there be altogether at the end of a business conference if the ten people present all shake hands with each other once?
Wiki User
∙ 7y ago
There will be 45 handshakes (assuming that each person doesn't repeat who they shake hands with).
Use the following formula for this one (n*(n-1))/2 where n is number of people...so if 10 people its (10 x 9) / 2 = 45 handshakes, if 7 people its (7 x 6) / 2 = 21 handshakes etc.
Wiki User
∙ 7y ago
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If every person at a party shakes the hand of every other person and there were 105 handshakes in all How many persons were present at the party?
The answer is 15 people. Each shook hands with 14 others, and there are half that many handshakes (pairs). The total number of pairs (distinct handshakes) within the group is defined by the formula T = [n!/(n-2)!] /2 Given T = 105 we get n!/(n-2)!=210 which implies n(n-1)=210 on solving we get n=15
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If every person at a party shakes the hand of every other person and there were 105 handshakes in all How many persons were present at the party?
The answer is 15 people. Each shook hands with 14 others, and there are half that many handshakes (pairs). The total number of pairs (distinct handshakes) within the group is defined by the formula T = [n!/(n-2)!] /2 Given T = 105 we get n!/(n-2)!=210 which implies n(n-1)=210 on solving we get n=15
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