There are: (2*36)+9 = 81 inches
36 in = 1 yd ⇒ 20 in = 20 ÷ 36 yd = 5/9 yd ≈ 0.56 yd
4/9 or 0.4444 square yards in 24 inches x 24 inches (2/3 yd x 2/3 yd).
12 inches x 12 inches = 144 square inches 1/3 yd x 1/3 yd = 1/9 square yard Those are probably the 2 most common equivalents.
15 yd^2 x 9 ft^2/yd^2 = 135 square feet
3 yd 2 ft - 1 ft 5 in = 9 ft + 2 ft - 1 ft - 5 in = 10 ft - 5 in = 9 ft 7 in = 3 yd 7 in
153in = 4yd and 9 inches because 1 yd =36 in 36 times 4=144 NOW how many inches is there left to 153 inches 9 so the answer is 4 yd 9 in
36 in = 1 yd ⇒ 20 in = 20 ÷ 36 yd = 5/9 yd ≈ 0.56 yd
4/9 or 0.4444 square yards in 24 inches x 24 inches (2/3 yd x 2/3 yd).
1 yard =36 inches 1/2 yard= 18 inches
1 yd = 3 ft 29/ 3 = 9 and a remainder of 2 answer: 9 yards, 2 feet
56 inches = 1 yd 1ft 8 ins.
114 inches, because 12 x 9 = 108 + 18 = 126
12 inches x 12 inches = 144 square inches 1/3 yd x 1/3 yd = 1/9 square yard Those are probably the 2 most common equivalents.
15 yd^2 x 9 ft^2/yd^2 = 135 square feet
3 yd 2 ft - 1 ft 5 in = 9 ft + 2 ft - 1 ft - 5 in = 10 ft - 5 in = 9 ft 7 in = 3 yd 7 in
There are 36 inches in one yard. Therefore, 1 yard 9 inches is equal to 36 + 9 = 45 inches.
No, you cannot construct a triangle with side lengths 2 yd, 9 yd, and 10 yd. This is because the sum of the lengths of the two shorter sides (2 yd + 9 yd = 11 yd) must be greater than the length of the longest side (10 yd) to satisfy the triangle inequality theorem. Since 11 yd is greater than 10 yd, these lengths do not form a triangle.