1 mA is equal to 0.001 A.
Infinitely many. Infinitely many. Infinitely many. Infinitely many.
Infinitely many. Infinitely many. Infinitely many. Infinitely many.
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mA stands for milliAmpere. milli- means 1/1000th.So 1mA = 0.001 A400 mA = 0.400 A
1 mA is equal to 0.001 A.
Around .0007 Watts. Watts=Amps x Volts 0.0007W=0.001A(1mA) x 0.7V
It varies depending on where in the body the current is passing through. Less than .1mA, if it's across the heart.
If you're looking for a definition, it's: the voltage at which, a diode can be considered a "short circuit" or low-value resistor It varies with each diode, but most have approximately 0.6 or 0.7 Volts across them when you get almost 1mA flowing FORWARD through them. For light emitting diodes (LEDs), it varies between diodes and is largely dependent on the colour of the light. Green ones typically have 1.3V @ 1mA, red = 1.8V @ 1mA, and higher for other colours. Infrared LEDs usually have 1.1V @ 1mA. Higher cutoff voltages occur at higher forward currents, meaning that at 1mA, Vf might be 1.8V for a certain diode, but at 10mA Vf is maybe 1.9V. One important side note is that reverse current is still possible, but is so small it's usually negligible. Also, it's not recommended to force current backwards through a diode (exception: Zener diodes) because it usually requires a higher voltage to accomplish this. The cutoff voltage of a diode is the maximum voltage that the diode can withstand in the revers biase above which the device will be destroyed.
if you want to measure a wide range of current, example 1mA to 200A (if the device is intended for the metering and protection), normally CT and rocoil is used together, it is difficult to make rocoil sensitive in range of 1mA, but you can do the task with the CT, but the same CT gets saturated above 5A, in that case rocoil start measuring, since rocoil is air core it wont saturate.
The collector current is a multiple of the base current due to the inherent design of the BJT. In circuit analysis, barring knowing the exact amplification, I've used 50 many times - so if you have 20 uA flowing in the base, the collector current should be ~ 1mA, and the emmiter will be ~1.02mA.
Yes. Almost every electronic device consumes energy, however small. However the power draw of a voltage regulator is extremely tiny, typically less than 1mA. As such, they usually save more power than they consume.
I think you mean the meter is rated at 1K ohms per volt. It means that with a series resistance designed to give FSD at any required voltage, the total series resistance must be 1000 ohms per volt (100K ohms for 100volts) . This is because 1K ohms per volt is just another way of saying that the full scale reading occurs at 1mA current. In that case a full scale deflection for 100 volts applied, 1mA is obtained with a total resistance (meter + added resistance) of 100 kOhms which is your loading resistance.
1 amp is larger than 1 milliamp. 1 amp is equivalent to 1000 milliamps.
The ratio of the 10 mA current in a muscular contraction to the 1 mA current in a tingling sensation is 10:1. This means that the current experienced during a muscular contraction is 10 times greater than the current experienced during a tingling sensation.